\(A\text{×}0,6+A:0,25=40,94\)

\(A\text{×}0,6+A\text{×}4=40,94\)

\(A\text{×}\left(0,6+4\right)=40,94\)

\(A\text{×}4,6=40,94\)

\(A=40,94:4,6\)

\(A=8,9\)

\(\dfrac{3}{2}x+\dfrac{3}{7}=-\dfrac{4}{5}\)

\(\Leftrightarrow\dfrac{3}{2}x=-\dfrac{43}{35}\)

\(\Leftrightarrow x=-\dfrac{86}{105}\)

Vậy \(x=-\dfrac{86}{105}\)

\(-\dfrac{11}{12}x+0,25=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x+\dfrac{1}{4}=\dfrac{5}{6}\)

\(\Leftrightarrow-\dfrac{11}{12}x=\dfrac{7}{12}\)

\(\Leftrightarrow x=-\dfrac{7}{11}\)

Vậy \(x=-\dfrac{7}{11}\)

\(\left(x-2\right)^2=1\)

\(\Leftrightarrow\left(x-2\right)^2-1=0\)

\(\Leftrightarrow\left(x-2-1\right)\left(x-2+1\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = {3; 1}\(\left(2x-1\right)^3=-8\)

\(\Leftrightarrow2x-1=-2\)

\(\Leftrightarrow2x=-1\)

\(\Leftrightarrow x=-\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\)

       (x - 2)² = 1

<=>\(\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.< =>\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

Vậy x = 3; 1

(2x - 1)³ = -8

<=> 2x - 1 = -2

<=> 2x = -1

<=> x = \(\dfrac{-1}{2}\)

Vậy x = \(\dfrac{-1}{2}\)

\(|\) 2,5 - x\(|\) = 1,3

1,6- \(|\)x - 0,2 \(|\)= 0

13^x = 169

\(\dfrac{-2}{x}\)=\(\dfrac{-x}{8\dfrac{ }{25}}\)

\(\dfrac{x}{-15}\)=\(\dfrac{-60}{x}\)

\(|\)x\(|\)+0,573=2

TÌM X:

a) 2x - 3 = \(\frac{1}{2}\)

2x = \(\frac{1}{2}+3\)

2x = \(\frac{7}{2}\)

x = 2 : \(\frac{7}{2}\)

x = 2 . \(\frac{2}{7}\)

x = \(\frac{4}{7}\)

b) /x+1/ = 0.25

/x+1/ = \(\frac{1}{4}\)

\(\orbr{\begin{cases}x+1=\frac{1}{4}\\x+1=-\frac{1}{4}\end{cases}}\)

\(\orbr{\begin{cases}x=\frac{1}{4}-1\\x=-\frac{1}{4}-1\end{cases}}\)

\(\orbr{\begin{cases}x=-\frac{3}{4}\\x=-\frac{5}{4}\end{cases}}\)

c) 32 : 2x = 2

\(2x=32:2\)

\(2x=16\)

\(x=16:2\)

\(x=8\)

~GOOD STUDY~

a) 2x-3=1/2

=> 2x=1/2+3

=> 2x=7/2

=> x=7/2:2

=> x=7/4

b) |x+1|=0.25

=> \(\orbr{\begin{cases}x+1=0,25\\x+1=-0,25\end{cases}}\)=>\(\orbr{\begin{cases}x=0,25-1\\x=-0,25-1\end{cases}}\)=>\(\orbr{\begin{cases}x=-0,75\\x=-1,25\end{cases}}\)

870 - x : 11 x 87 = 261
         x : 11 x 87 = 870 - 261
         x : 11 x 87 =      609
         x : 11         = 609 : 87
         x : 11         =       7
         x                = 7 x 11
         x                =    77
x : 0.25 x 2.3 = 6.9
x : 0.25          = 6.9 : 2.3
x : 0.25          =      3
x                    = 3 x 0.25
x                    =     0.75
2 x (y + y) = 8.16
      y + y   = 8.16 : 2
      y x 2   =     4.08
      y         = 4.08 : 2
      y         =     2.04
y x 1.5 + y + y x 7.5 = 59.8
y x (1.5 + 1 + 7.5)    = 59.8
y x        10                = 59.8
y                               = 59.8 : 10
y                               =      5.98

m : 1/6 + m : 0.25 = 152
m : 1/6 + m : 1/4   = 152 
m x 6 + m x 4       = 152
m x (6 + 4)            = 152
m x     10               = 152
m                           = 152 : 10
m                           =       15.2

m : 1/3 + m : 0.25 = 1.4
m : 1/3 + m : 1/4   = 1.4
m x 3 + m x 4        = 1.4
m x (3 + 4)             = 1.4
m x     7                 = 1.4
m                           = 1.4 : 7
m                           = 0.2   

b) Ta có: \(3+\left(x-5\right)=2\left(3x-2\right)\)

\(\Leftrightarrow3+x-5=6x-4\)

\(\Leftrightarrow x-2-6x+4=0\)

\(\Leftrightarrow-5x+2=0\)

\(\Leftrightarrow-5x=-2\)

\(\Leftrightarrow x=\dfrac{2}{5}\)

Vậy: \(S=\left\{\dfrac{2}{5}\right\}\)

c) Ta có: \(2\left(x-0.5\right)+3=0.25\left(4x-1\right)\)

\(\Leftrightarrow2x-1+3=x-\dfrac{1}{4}\)

\(\Leftrightarrow2x+2-x+\dfrac{1}{4}=0\)

\(\Leftrightarrow x+\dfrac{9}{4}=0\)

\(\Leftrightarrow x=-\dfrac{9}{4}\)

Vậy: \(S=\left\{-\dfrac{9}{4}\right\}\)

d) Ta có: \(2\left(x-\dfrac{1}{4}\right)-4=-6\left(-\dfrac{1}{3}x+0.5\right)+2\)

\(\Leftrightarrow2x-\dfrac{1}{2}-4=2x-3+2\)

\(\Leftrightarrow2x-\dfrac{9}{2}=2x-1\)

\(\Leftrightarrow2x-2x=-1+\dfrac{9}{2}\)

\(\Leftrightarrow0x=\dfrac{7}{2}\)(vô lý)

Vậy: \(S=\varnothing\)

b. 

→ -2 + x = 6x - 4

→ -2 + 4 = 6x - x

→ 2 = 5x

→ x = \(\dfrac{2}{5}\) 

Vậy, phương trình có tập nghiệm S = {\(\dfrac{2}{5}\)}

8,1:0,6x1375+1,5x0,25x9=148527/8=18565,875

105+205+795+895=2000

8,1 : 0,6 * 1375 + 1,5 * 0,25 * 9

= 13,5 * 1375 + 1,5 * 0,25 * 9

= 18562 , 5 + 0,375 * 9 

= 18562 , 5 + 3,375 

= 18565 , 375

b ) 105 + 205 + 795 + 895 

= ( 105 + 205 ) + ( 795 + 895 )

= 310+ 1690

= 2000

tk tui nha 

hihi mơn mọi người trước nhé ! ( always smile ) 

\(\frac{-11}{12}\)  .x+0.25 = \(\frac{5}{6}\)

\(\frac{-11}{12}\) .x+ \(\frac{1}{4}\)= \(\frac{5}{6}\)

\(\frac{-11}{12}\).x            =\(\frac{5}{6}\)- \(\frac{1}{4}\)

\(\frac{-11}{12}\).x            = \(\frac{7}{10}\)

                 x            = \(\frac{7}{10}\)- \(\frac{-11}{12}\)

                  x            = \(\frac{47}{60}\)

k cho mik nha,chúc bn học tốt

\(\frac{-11}{12}\cdot x+0,25=\frac{5}{6}\)

\(\Rightarrow\frac{-11}{12}\cdot x+\frac{1}{4}=\frac{5}{6}\)

\(\Rightarrow\frac{-11}{12}\cdot x=\frac{5}{6}-\frac{1}{4}\)

\(\Rightarrow\frac{-11}{12}\cdot x=\frac{7}{12}\)

\(\Rightarrow x=\frac{7}{12}:\frac{-11}{12}\)

\(\Rightarrow x=\frac{7}{-11}\)

vay___

\(-\dfrac{11}{12}\cdot x+0,25=\dfrac{5}{6}\\ -\dfrac{11}{12}\cdot x=\dfrac{5}{6}-\dfrac{1}{4}\\ -\dfrac{11}{12}\cdot x=\dfrac{7}{12}\\ x=\dfrac{7}{12}:-\dfrac{11}{12}\\ x=-\dfrac{7}{11}\\ Vậyx=-\dfrac{7}{11}\)

b: \(x+\dfrac{5}{6}=\dfrac{3}{8}\)

=>\(x=\dfrac{3}{8}-\dfrac{5}{6}\)

=>\(x=\dfrac{9}{24}-\dfrac{20}{24}=-\dfrac{11}{24}\)

c: \(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{5}{6}\)

=>\(\dfrac{2}{3}x=\dfrac{5}{6}+\dfrac{1}{2}=\dfrac{8}{6}=\dfrac{4}{3}\)

=>2x=4

=>x=4/2=2

d: \(\dfrac{x}{7}=\dfrac{6}{-21}\)

=>\(\dfrac{x}{7}=\dfrac{-2}{7}\)

=>x=-2

e: \(\left(\dfrac{7}{3}x-0,6\right):\dfrac{3^2}{5}=1\)

=>\(\dfrac{7}{3}x-0,6=\dfrac{3^2}{5}=1,8\)

=>\(\dfrac{7}{3}x=2,4\)

=>\(x=2,4:\dfrac{7}{3}=2.4\cdot\dfrac{3}{7}=\dfrac{7.2}{7}=\dfrac{36}{35}\)

f: \(\dfrac{x}{45}=\dfrac{5}{6}+\dfrac{-29}{30}\)

=>\(\dfrac{x}{45}=\dfrac{25}{30}-\dfrac{29}{30}=-\dfrac{4}{30}=-\dfrac{2}{15}\)

=>\(x=-\dfrac{2}{15}\cdot45=-6\)

g: \(\left(4,5-2x\right)\cdot\left(-\dfrac{1^4}{7}\right)=\dfrac{11}{14}\)

=>\(4,5-2x=\dfrac{11}{14}:\dfrac{-1}{7}=\dfrac{-11}{2}\)

=>\(2x=4,5+\dfrac{11}{2}=\dfrac{20}{2}=10\)

=>x=10/2=5

h: \(-\dfrac{2}{7}+\dfrac{4}{7}x=\dfrac{5}{7}\)

=>\(\dfrac{4}{7}x=\dfrac{5}{7}+\dfrac{2}{7}=\dfrac{7}{7}\)

=>4x=7

=>\(x=\dfrac{7}{4}\)